Question

Construct an equilateral triangle abc with each side 5 cm then construct another triangle whose side 5/3 times the corresponding sides of triangle abc

Answer 1

Answer:

To construct an equilateral triangle with each side 5 cm.

Step-by-step explanation:

First Draw a striaght line with 5 cm dimension and Mark line as AB.

Option 1. Using compass :

Draw an arc From point A of line with dimension of 5 cm

Draw an arc From point A of line with dimension of 5 cmthen Draw another arc from Point B of line with dimension of 5 cm

Draw an arc From point A of line with dimension of 5 cmthen Draw another arc from Point B of line with dimension of 5 cmand mark intersection point of ARC as C

Draw an arc From point A of line with dimension of 5 cmthen Draw another arc from Point B of line with dimension of 5 cmand mark intersection point of ARC as Cnow join AC & BC

Draw an arc From point A of line with dimension of 5 cmthen Draw another arc from Point B of line with dimension of 5 cmand mark intersection point of ARC as Cnow join AC & BCΔABC is an equilateral triangle with 5 cm each side

Option 2 . Using Protractor

Draw a line with Angle 60° with line AB from point A with dimension of 5 cm and Mark the point aa C.

Draw a line with Angle 60° with line AB from point A with dimension of 5 cm and Mark the point aa C.Join point B & C with straight line

Draw a line with Angle 60° with line AB from point A with dimension of 5 cm and Mark the point aa C.Join point B & C with straight lineΔABC is an equilateral triangle with 5 cm each side

Draw a line with Angle 60° with line AB from point A with dimension of 5 cm and Mark the point aa C.Join point B & C with straight lineΔABC is an equilateral triangle with 5 cm each sideTo draw another triangle use the same process but dimension used should be (2/3) of 5

Draw a line with Angle 60° with line AB from point A with dimension of 5 cm and Mark the point aa C.Join point B & C with straight lineΔABC is an equilateral triangle with 5 cm each sideTo draw another triangle use the same process but dimension used should be (2/3) of 5= 5*2/3 = 10/3

Draw a line with Angle 60° with line AB from point A with dimension of 5 cm and Mark the point aa C.Join point B & C with straight lineΔABC is an equilateral triangle with 5 cm each sideTo draw another triangle use the same process but dimension used should be (2/3) of 5= 5*2/3 = 10/3= 3.33 cm

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Answer 2

AB'C' is the required triangle

Step-by-step explanation:

STEPS :

• draw  a line segment AB = 5 cm
• with A as a center and radius = 5 cm  draw an arc
• with B  as a center and radius = 5 cm  draw an arc , which cuts the previous arc at point C
• ABC is the equilateral triangle
• now , draw a ray AX mark 5 points on it at equal distances , say $A_1,A_2,A_3,A_4,A_5$
• now, join $A_5 B$ , and make a line $A_3B'$ parallel to it
• similarly draw a line $B'C'$  parallel to BC
• AB'C' is the required triangle

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