Construct an equilateral triangle if its altitude is 3.2cm.
Answers
Answered by
39
all sides are equal and all angles are equal i.e., each angle is of 60°.
Given, altitude of an equilateral triangle say ABC is 3.2 cm. To construct the ΔABC use the following steps.
1.Draw a line PQ.
2.Take a point D on PQ and draw a ray DE ⊥ PQ.
3.Cut the line segment AD of length 3.2 cm from DE.
4.Make angles equal to 30° at A on both sides of AD say ∠CAD and ∠BAD, where B and C lie on PQ.
5.Cut the line segment DC from PQ such that DC = BD
Join AC
Given, altitude of an equilateral triangle say ABC is 3.2 cm. To construct the ΔABC use the following steps.
1.Draw a line PQ.
2.Take a point D on PQ and draw a ray DE ⊥ PQ.
3.Cut the line segment AD of length 3.2 cm from DE.
4.Make angles equal to 30° at A on both sides of AD say ∠CAD and ∠BAD, where B and C lie on PQ.
5.Cut the line segment DC from PQ such that DC = BD
Join AC
Answered by
19
all sides are equal and all angles are equal i.e., each angle is of 60°.
Given, altitude of an equilateral triangle say ABC is 3.2 cm. To construct the ΔABC use the following steps.
1.Draw a line PQ.
2.Take a point D on PQ and draw a ray DE ⊥ PQ.
3.Cut the line segment AD of length 3.2 cm from DE.
4.Make angles equal to 30° at A on both sides of AD say ∠CAD and ∠BAD, where B and C lie on PQ.
5.Cut the line segment DC from PQ such that DC = BD
Join AC
Similar questions