Question

construct an equilateral triangle similar to the equilateral triangle of 4cm with a scale factor 4/3.

Answer 1

Steps of construction:-

1.Draw BC=4 cm.

2.Taking B and C as centre and radius equal to 4cm draw arcs and join AB and AC thus ,equilateral ∆ABC is formed.

3.With B as a centre draw a ray BX making an acute angle CBX with BC.

4.With B as centre and with any radius Draw equal arcs such that BB1=B1B2=B2B3=B3B4 are equal .

5.Join B4C.

6.Draw B3DllB4C such that; BB3/B3B4=BD/DC {By using Thale's theorem}.

7.Let B3D intersects BC at D making DEllCA such that BD/DC=BE/EA. {By BPT}.

8.Hence,∆BED is formed which is 4/3 of ∆ABC.





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