Construct an equilateral triangle whose altitude is 5.5 cm
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1. Draw a rough sketch with given measure
2. Draw the BC = 5.5 cm
3. Measure 5.5 cm in your compass
4. And keeping B as center draw an arc, Also keeping C as center draw an arc of some radius.
5. Name the point of inter section of two two arcs as A C join AB and AC
Therefore,
∆ ABC is formed
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