Question

construct an equilateral triangle whose altitude measure 4.5 centimetre

Answer 1

Answer:

Step-by-step explanation:

Steps of construction

1. Draw a line PQ

2. Take any point L on this line

3. construct perpendicular AL on PQ

4. Cut a line segment AD fron D equal 4.5 cm

5. Make an angle of 30 ° at A on both sides of AD, say ∠CAD and ∠BAD

where B and C lie on XY

Hence , ABC is the required triangle

Checked

∠A = 30° + 30°

       = 60°

AL ⊥BC

So, the Al is the altitude of equilateral  triangle

Answer 2

Answer:

Draw a line PQ.

Take any point L on this line.

Construct perpendicular AL on PQ.

Cut a line segment AD from D equal to 4.5 cm.

Make angles equal to 30° at A on both sides of AD, say ∠CAD and ∠BAD where B and C lie on XY.

Then, ABC is the required triangle.

Justification:

Since ∠A = 30° + 30° = 60° and AL ⊥ BC,

Therefore, ∆ABC is an equilateral triangle with altitude AL = 4.5 cm.