construct an equilateral triangle whose sides are 3cm .then construct a triangle whose sides are twice the first triangle
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We assume ABCD be the quadrilateral having sides AB, BC, CD, DA and ∠ACB = 90∘.
We take a diagonal AC, where AC divides ABCD into two triangles ΔACB and ΔADC
Base = BC = 8 cm; Height = AC = 15 cm
Area of triangle ADC, say A2 having sides a, b, c and s as semi-perimeter is given by
, where
a = AD = 9 cm; b = DC = 12 cm; c = AC = 15 cm
Area of quadrilateral ABCD, say A
A = Area of ∆ACB + Area of ∆ADC
Perimeter of quadrilateral ABCD, say P
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