Construct an equilateral triangle with sides 5 cm and justify the construction.
Construct perpendicular bisectors of all sides and angle bisectors of all angles of
the same triangle. Write the inference of your observation.
Answers
Given : an equilateral triangle with sides 5 cm
To Find : Construct an equilateral triangle
Construct perpendicular bisectors of all sides and angle bisectors of angles of the same triangle.
Solution:
Step 1 : Draw a line segment B = 5 cm
Step 2 : Using compass width = 5 cm and taking A as center , draw an arc
Step 3 : Keeping compass width same and taking B as center draw an arc intersecting previous arc at C
Step : Join AC & BC
equilateral triangle is constructed
Construct perpendicular bisectors
Using suitable compass width and taking A as center Draw arc on both sides of AB
Keeping compass width same and taking B as center Draw arcs on both sides intersecting arc drawn in previous step at M & N
Draw a line passing through M & N which is perpendicular bisector of AB
Similarly draw perpendicular bisector of AC & BC
Construct angle bisector
Using Suitable compass width and taking A as center draw arc intersecting AB at X & AC at Y
Using Suitable compass width and taking X as center draw an arc
Keeping compass width same and taking Y as center draw an arc intersecting arc drawn in previous step at Z
Draw a ray passing through AZ
AZ is angle bisector of angle A
Similarly draw angle bisector of B & C
Perpendicular bisector & angle bisector all intersects at same point
Learn More:
construct a right angle triangle in which base if two times of the ...
brainly.in/question/14146138
Construct triangle ABC,in which BC=5.2 cm angle ACB=45° and ...
brainly.in/question/7727032
Answer:
please mark me brainliest
Step-by-step explanation:
Let's assume side of equilateral triangle is 5.5 cm.
Steps of construction :
1) Draw a line segment AB of length 5.5 cm.
2) Taking 5.5 cm as radius, and A as centre, draw an arc.
3) Taking 5.5 cm as radius, and B as centre, draw another arc.
4) Let C be the point where the two arcs intersect . Join AC and BC and label the sides.
Thus, △ ABC is the required equilateral triangle.
Justification :
By construction, AB = AC = BC (Radius of equal arcs)
Since, all sides are equal , therefore, △ ABC is an equilateral triangle.