Construct an isoceles triangle ABC with AB=AC base=7cm, altitude from A=6.5
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1.Draw any line segment BC = 7
2.Draw ‘p’ the perpendicular bisector of BC and let it intersect BC in R
3.Cut off PQ = 6.5 cm.
4.Join QB.
5.Draw the perpendicular bisector of BQ and let it intersect PQ in A.
6. Join AB and AC. Thus, ΔABC is the required triangle.
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