construct an isoscales triangle ABC where mAC=mBC=5cm
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Steps of construction :
Draw any line segment BC = 4 cm.
Draw 'p' the perpendicular bisector of BC and let it intersect BC in R.
Cut off PQ = 6.5 cm.
Join QB.
Draw the perpendicular bisector of BQ and let it intersect PQ in A.
Join AB and AC. Thus, ΔABC is the required triangle.
Step-by-step explanation:
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