construct an isosceles triangle whose base is 4 cm and vertex angle is 30 degree .draw perpendicular from the vertex on base
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In an Isosceles Δ, base angles are equal.
∴180°-30°= 2∠A
∴150°=2∠A
∴75° = each base angle
Step1: Draw a line segment AB of length 4cm
Step2: Construct a 90° and a 60° angle at A.
Step3: Bisect the angle between the 90°and the 60° to obtain a 75°. Extend the Angle Bisector to a point D
Step4: Repeat the process at B, extend the angle bisector to a point E
Step5: Name the point of intersection of AD and BE as C.
Result: ΔABC is an isosceles Δ with base 4cm, vertex angle 30°.
∴180°-30°= 2∠A
∴150°=2∠A
∴75° = each base angle
Step1: Draw a line segment AB of length 4cm
Step2: Construct a 90° and a 60° angle at A.
Step3: Bisect the angle between the 90°and the 60° to obtain a 75°. Extend the Angle Bisector to a point D
Step4: Repeat the process at B, extend the angle bisector to a point E
Step5: Name the point of intersection of AD and BE as C.
Result: ΔABC is an isosceles Δ with base 4cm, vertex angle 30°.
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