construct an isosceles triangle with base of 6 cm and its base angles of 70 degree construct a parallelogram and angle which is equal in the area of the triangle
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REQUIRED TO CONSTRUCT:
An isosceles triangle ABC, Base BC = 6 cm, Vertical angleA = 40°
STEPS OF CONSTRUCTION: This triangle can be constructed using alternate segment theorem.
(1) After drawing a ray, cut off a segment BC = 6 cm
(2) Draw an angle CBX = vertical angle 40° on the other side of vertex A.
(3) Now, on BX, at point B, construct a perpendicular BO.
(4) Construct a perpendicular bisector of BC, which intersects BO at point O
(5) Taking O as centre , BC/2 radius, draw a circle, which passes through B & C.
(6) This perpendicular bisector, intersects the circle at point A.
(5) O will be the centre of the circle, passing through A, B, & C.
(6) Join A,B & join A,C.
Triangle ABC is the required triangle.
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