Construct circumcircle of ∆PQR .If QR=6cm,PR=7cm and angle P=120°
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I will give you step just follow it.
1)just take QR as a base and make line segment of 6c.m
2) with R as a pointer just take 7 cm radius and draw an Arc. and name them P.
3) with the Q as a center construct 120 angle and you find that the first arc that you drawn in step two is just intersect each other and the point where it intersect name that point as P
1)just take QR as a base and make line segment of 6c.m
2) with R as a pointer just take 7 cm radius and draw an Arc. and name them P.
3) with the Q as a center construct 120 angle and you find that the first arc that you drawn in step two is just intersect each other and the point where it intersect name that point as P
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