construct grouped frequency distribution table for the given data with a size of class interval of 10...the given numbers are 33,8,5,7,25,50,25,48,56,33,28,22,15,62,59,16,14,19,24,35,26,9,12,46,63,32,5,22,11,42,23,52,48,62,10,24,43,51,37,48,36
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Explanation:
⇒ In given data minimum value is 5 and maximum value is 63
⇒ Range =63−5=58
⇒ Number of class interval =6 class interval (Average)
⇒ Length of the class interval =
6
58
=9.6≈10
Class−interval Frequency
0−9 5
10−19 8
20−29 10
30−39 7
40−49 7
50−59 5
60−69 3
Total 45
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