Question

construct NTS where NT = 5.7cm, TS=7.5cm.
and LNTS = 110° and draw incircle and circum circle .
of it​

Answer 1

Answer:

Steps of construction:

• Draw a line ST = 7.5 cm.
• With T as centre draw an angle ∠ STX = 110°.
• With T as centre and 5.7 cm as radius, cut an arc on XT and name the point of intersection as N.
• Join SN. Δ NTS is thus obtained.
• Draw the perpendicular bisectors of the lines ST and NT.

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