Math, asked by learner8481, 1 year ago

construct parallelogram ABCD with AB=4cm,BC=6cm and angle B=60 DEGREE

Answers

Answered by rakeshmohata
23
To construct a structure it requires few processes.

=> ABCD is a parallelogram

=> Angle B = 60°
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=> So make a straight line more than 6 cm..

=> take the length BC on compass and cut the straight line with same length.

=> take a few distance from point B, make a semicircle and putting it on the point where it coincides with the straight line. Cut the arc on that semicircle.. Thus the angle will be 60°

=> With the same measurement cut an arc on point C too making 60° angle

=> Draw straight lines from B that connects the bisection of arc and extend it further.

Similarly do that from C.

=> take Ab length on compass and cut the straight line such that a cross be made on that.

Similarly on other side too.

=> now connect the two cuts..

U will get the required parallelogram.
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Checking
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=> measure each side by scale and check whether AD and BC are of required lengths and AB and BC are of required lengths.

=> check the angle with protractor.
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Hope this is ur required answer

Proud to help you
Attachments:

rakeshmohata: hope u got it!!
learner8481: what is the angle degree
rakeshmohata: 60°
learner8481: u drew the arc
learner8481: plz can u mark the degree also
learner8481: plz
rakeshmohata: ok
learner8481: its okay i dont want
learner8481: plz am leaving right now
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