Question

Construct ∆PQR if PQ = 5cm, PQR = 105° and QRP = 40°.

Answer 1

Step-by-step explanation:

1. Draw PQ of lenght 5cm.

2. At point Q, construct angle 105°. Then draw a ray QX on same angle.

Now, on finding angle RPQ.

According to angle sum property,

RPQ + QRP + RQP = 180°

x + 40 + 105 = 180°

x = 180° - 145°

x = 35°

3. Now, on drawing 35° on point P. Then draw a ray PX on same angle.

4. Point of intersection of both rays is point R.

5. Join all the sides together.

∆PQR with given measures is ready.

Answer 2

Answer:

(1) Draw PQ = 5cm.

(2) At point Q construct angle 105°.

Then draw a ray QX on same angle.

Now, we know that sum of all angles of a ∆ is 180° .

RPQ + QRP + RQP = 180°

x + 40 + 105 = 180°

x = 180° - 145°

x = 35°

(4) Now, on drawing 35° on point P draw a ray PX on same angle.

(5) Point of intersection of both rays is point R.

(6) Join all the sides together.

∆PQR is the required ∆ ..