Question

construct ▲ PQR if pq - 5cm pqr - 105° and qrp-40°
( solve it in a paper step wise) ​

Answer 1

hope it will help you

Answer 2

Steps of construction:

1) Draw a line segment PQ=5cm.

2)Construct <PQR=105° and mark the point R. Extend it and name that Ray as x.

3)With R as a centre, construct <QRP=40° and extend that Ray and name it y.

4)Join R and P

PQR is the required triangle