Construct PQR such that QR equal to 6cm angle Q and R equal to 60 measure other two sides of triangle and name the triangle
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let third angle is then
60°+60°+x=180
x=60°
thus ∆ is equilateral ∆
and other side is of 6cm
hope this will help you.
60°+60°+x=180
x=60°
thus ∆ is equilateral ∆
and other side is of 6cm
hope this will help you.
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