Construct ∆ PYQ such that PY= 6.3 cm,
YQ = 7.2 cm, PQ = 5.8 cm. If
YZ/YQ=6/5
then construct ∆ XYZ similar to ∆ PYQ.
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draw a line 6.3 centimetres and take a compass take a 7.2 centimetre arc them another take a 5.8 cm joint you make a similar triangle such that way of xyz
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