Question

construct quarditerial :AB=6cm, BC=8cm,CD=6cm ,AD=8cm and AC=10cm

Answer 1

Answer:

A circle with centre O, touches the sides AB,BC,CD,DA, at P,Q,R,Srespectively.

Join OP,OQ,OR,OS

Now two tangents drawn from an external C

Now two tangents drawn from an external Cpoint to a circle subtend equal angles at

Now two tangents drawn from an external Cpoint to a circle subtend equal angles at the centre.

∴(i)AP=AS,

(ii)BP=BQ,

(iii)CR=CQ,

(iv)DR=DS

(iv)DR=DSAB=6 cm,BC=7 cm,CD=4 cm

Now from above solution we have

AB+CD=BC+AD

⇒10=7+AD

⇒AD=3 cm

Step-by-step explanation:

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