Math, asked by manishaaingh5837, 9 months ago

construct the following quadrilaterals. (iii) Rhombus BEND BN= 5.6 cm DE= 6.5 cm Please Answer It Correctly​

Answers

Answered by Anonymous
1

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Rhombus BEND BN= 5.6 cm DE= 6.5 cm

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BEND Rhombus Constructed

Construct the rhombus BEND

BN = 5.6 cm

DE = 6.5 cm

We need to Draw Rhombus BEND

=> BN  & DE are diagonals

Diagonals of Rhombus bisect each other Perpendicularly

So, First We will Draw  DE = 6.5 cm

Then Take the midpoint of DE as O  6.5/2 = 3.25 cm

Then draw Perpendicular on both sides of length = 5.6/2 = 2.8 cm Each and we will get B & N Points now join BD & BE & ND & NE

We will get BEND Rhombus

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