Construct the right angled ΔPQR, where m∠Q=90° QR=8cm and PR=10c.m
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Step-by-step explanation:
ok see,To construct: A right angled △PQR where m∠Q=90 degree QR=8cm and PR=10cm...
Steps of construction:
(a) Draw a line segment QR=8cm
(b) At point Q, draw QX⊥QR
(c) Taking R as centre, draw an arc of radius 10cm
(d) This arc cuts QX at point P
(e) Join PQ
It is the required right angled triangle PQR..
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