Question

construct the triangle PQR such that PQ=5cm, PR=6cm and <QPR=60° and locate it's centroid.​

Answer 1

Hi,

I can help you with the steps needed to answer the question.

1) Draw a straight line PQ = 5cm

2) Located angle 60 (Using a circular or a protractor), Now, Angle QPR = 60

3) Let PR = 6cm

4) Join R and Q

Locating the centroid:

1) Locate the centre of each of the sides of the triangle PQ, QR, RP.

2) Name the centres of the sides PQ, QR, RP as A, B, C respectively.

3) Join PB, QC, RA.

4) The point that PB, QC, RA meet is the centroid of the triangle.

Hope it helps !!

Answer 2

Answer:

Construct <RQS =60° with the help of compass. Produced XP downwards to a point X'. Set off QX'=2.5 cm; Join X'R; Draw the perpendicular .