Question

construct triangle ABC if perimeter is 10.4 cm, angle B = 30* and angle C= 90*

Answer 1

Consider triangle ABC, angle B=30, angle C=90.
sin30=AC/AB=1/2
cos30=BC/AB=√3/2
therefore AC:AB:BC=1:2:√3
Now, let the common multiple be x
x+2x+√3x=10.4
4.732x=10.4
x=2.198

so the sides are 2.198, 4.396 & 3.807 cm.
hope this helps.