Construct triangle ABC in which angle B=45 , angle C=60 and AB+BC+CA=12cm
Answers
Answered by
13
Step-by-step explanation:
Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 11cm.
Step 2: Draw an angle of 60° at P and an angle of 45° at Q.
Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.
Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.
Step 5: Join AB and AC.
∴ ΔABC is the required triangle.
Answered by
16
∆ABC is required triangle.
Attachments:
Similar questions