Question

Construct triangle ABC,in which BC=5.2 cm angle ACB=45° and perimeter of triangle ABC is 10 cm?

Answer 1

Step 1: Draw a line segment BC 5.2 cm.
Step 2 : Draw ∠B = 45°.
Step 3 : With Center B and radius 4.8 cm, make an arc which intersects CX at D.
Step 4 : Join A to C.
Step 5 : Draw a perpendicular bisector of segment DB it intersect the line segment CD at point A.
Step 6 : Join C to A.
Please see the attached image

Answer 2

Given :  triangle ABC,in which BC=5.2 cm angle ACB=45° and perimeter of triangle ABC is 10 cm  

To Find : Construct triangle

Solution:

Perimeter of triangle is 10 cm

=> AB + BC + AC = 10 cm

BC = 5.2 cm

=> AB + 5.2 + AC = 10

=> AB + AC = 4.8 cm

4.8 < 5.2

AB + AC <  BC

Sum of two sides is not greater than third side

Hence triangle is not possible

Correct data BC 3.2

Step 1: Draw a line segment BC 3.2 cm.

Step 2 : Draw ∠C = 45° using protractor and draw a ray CX.

Step 3 : With Center C and radius 10-3.2= 6.8 cm, make an arc which intersects CX at D.

Step 4 : Join BD

Step 5 : Draw a perpendicular bisector of segment DB it intersect the ray CX at point A.

Step 6 : Join C to B

Triangle is constructed

Learn More:

https://brainly.in/question/12634157

Construct a triangle ABC in which Angle B = 60° Angle C = 30° and ...

https://brainly.in/question/15230017

construct a triangle ABC whose perimeter is 12.5cm and whose ...

https://brainly.in/question/8970196