Question

Prove the Converse of Pythagoras Theorem using a do the following in a quadrilateral ABCD angle b is equal to 90 education is equal to a b + BC + CD prove that angle ACB is equal to 90

Answer 1

Answer:

Step-by-step explanation:

In triangle PQR angleQ is 90°

PR2 = PQ2+QR2.....(Pythagoras thm)

= AB2+BC2... (construction)..I

= AC2.... (given)...II

PR2 = AC2

PR =AC.......III

triangle ABC =~ triangle PQR.... (SSStest)

Angle ABC = Angle PQR =90°