Construct triangle ABC in which BC = 6.3 cm, LB = 75° and AB + AC = 9 cm.( diagram nessecary ) please help me
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(1) Draw a base BC of length 6.3 cm
(2) Draw angle B=75
∘
(3) Open the compass for length AB+AC=9cm
(4) Cot an arc on ray BX at D
(5) Join CP
(6) Draw ⊥ bisector of CD.
(7) Mark point A where ⊥ bisector cut BD.
(8) Join AC Step-by-step explanation:
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