Question

construct triangle ABC such that AB=5.8 cm , BC+CA=7 cm and angle B=60 degree

Answer 1

1 make a line of 5.8 cm
2 then make 60 degree angle
3 make 7 cm of line
4 then join to point a
5 give that a name d
6 bisect ad
7 the line obtained by it join to B

Answer 2

Constructed ∆ABC is attached.

Given:

• A ∆ABC.
• AB=5.8 cm , BC+CA=7 cm and angle B=60°.

To find:

• Construction the ∆ABC.

Solution:

Steps of construction:

1. Draw line segment AB of 5.8 cm with the help of pencil and scale.
2. Draw $\angle B= 60^{\circ}$ with the help of compass. Let the ray is BX.
3. Draw an arc of 7 cm on ray BX. Let the point is L.
4. Join A and L.
5. Draw perpendicular bisector of AL with the help of compass. It intersects BX at point C.
6. Join A to C.
7. Construction of ∆ABC is over.

Verification:

On measurement it is found that

AC= 5.8 cm

and CB= 1.8 cm

Thus,

BC+CA=7 cm

Hence verified.

Learn more:

1) Construct a triangle PQR in which QR = 4.6 cm, Q= 45° and PQ+PR = 8.2 cm.

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2) Construct a Triangle ABC In which BC = 3.6 cm, AB + AC = 4.8 cm and angle B = 60 Degree

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