construct triangle ABC such that angleB =100 degree, BC=6.4 cm angle C =50 degree and constraction its incircle.
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Construct triangle ABC such that angleB =100 Construct triangle ABC such that angleB =100
=Steps of construction:
i. Construct ∆ABC of the given measurement.
ii. Draw the bisectors of ∠B and ∠C. Let these bisectors intersect at point I.
iii. Draw a perpendicular IM on side BC. Point M is the foot of the perpendicular.
iv. With I as centre and IM as radius, draw a circle which touches all the three sides of the triangle
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it's very easy to construct
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