construct triangle ABC such that angleB =100 degree, BC=6.4 cm angle C =50
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(i)Drawn BC = 6.4 cm.
△ABC is thus obtained.
(iii) Construct the angle bisectors of∠B and ∠C and let them meet at point O.
(iv) Through point O, draw a perpendicular to line. Let the perpendicular meet the line at point P.
(v) With O as centre and OP as radius , draw a circle inside the △ABC.
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