Construct Triangle ABC such that BC =6cm angle ABC =100° and AC - AB =2.5
Answers
Answered by
6
Step-by-step explanation:
Steps of construction:
(1) Draw seg BC of length 6cm.
(2) Draw ray BE such that ∠CBE=100
∘
(3) Take point D on the opposite of ray BE such that BD=2.5cm.
(4) Construct the perpendicular bisector of seg DC.
(5) Name the point of intersection of ray BE and the perpendicular bisector of DC as A.
(6) Draw seg AC.
Therefore, ΔABC is required triangle.
Answered by
6
Step-by-step explanation:
Steps of construction:
(1) Draw seg BC of length 6cm.
(2) Draw ray BE such that ∠CBE=100
∘
(3) Take point D on the opposite of ray BE such that BD=2.5cm.
(4) Construct the perpendicular bisector of seg DC.
(5) Name the point of intersection of ray BE and the perpendicular bisector of DC as A.
(6) Draw seg AC.
Therefore, ΔABC is required triangle.
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