construct triangle ABC such that BC is 8cm angle B = 45* AB=AC=3.5cm
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Step I: Draw the line segment BC = 8 cm and at point B, make an angle of 45°, say ∠XBC.
Step II: Cut the line segment BD = 3.5 cm (equal to AB − AC) on ray BX.
Step III: Join DC and draw the perpendicular bisector PQ of DC.
Step IV: Let it intersect BX at point A. Join AC. ΔABC is the required triangle.
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