Construct triangle ABC with BC = 6 cm , CA = 4 cm and angle BCA = 60 degree
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Construct a triangle ABC with BC=6 cm, angle A=60 degree and median AD through A is 5 cm long.Construct a triangle A 'BC ' similar to triangle ABC with BC '=8cm.Write steps of costruction.
Follow the steps to construct the triangle.
Step 1: Draw a line segment BC = 6 cm.
Step 2: At B, draw ∠CBE = 60°.
Step 3: Draw BF ⊥ BE.
Step 4: Draw the perpendicular bisector of BC intersecting BF at O.
Step 5: With O as centre and radius equal to OB or OC draw a circle.
Step 6: With D as centre and radius 5 cm, mark a point A on the circle.
Step 7: Join AB and AC. This gives the ΔABC.
Step 8: With B as centre and radius 8 cm, mark an arc which intersect BC produced in C'.
Step 9: Draw a line parallel to AC at C'.
Step 10: Extend the line segment BA, which intersect the line passing ttrough C' in A'.
but how to draw bf perpendicular to be in step 3
I hope it will help
Follow the steps to construct the triangle.
Step 1: Draw a line segment BC = 6 cm.
Step 2: At B, draw ∠CBE = 60°.
Step 3: Draw BF ⊥ BE.
Step 4: Draw the perpendicular bisector of BC intersecting BF at O.
Step 5: With O as centre and radius equal to OB or OC draw a circle.
Step 6: With D as centre and radius 5 cm, mark a point A on the circle.
Step 7: Join AB and AC. This gives the ΔABC.
Step 8: With B as centre and radius 8 cm, mark an arc which intersect BC produced in C'.
Step 9: Draw a line parallel to AC at C'.
Step 10: Extend the line segment BA, which intersect the line passing ttrough C' in A'.
but how to draw bf perpendicular to be in step 3
I hope it will help
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