Question

construct triangle DEF such that DE = 5cm, DF = 3cm and measure angle EDF = 90°​

Answer 1

Step-by-step explanation:

Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°

Draw a line segment DE of length 5 cm.

At D, draw a ray DX making 90° with DE.

With D as the center, draw an arc of radius 3cm to cut DX at point F.

Join EF to get the required triangle.

Thus, ΔDEF is the required triangle.