Question

construct triangle EFG in which angle F =60 degree and Angle B = 80 degree and perimeter is 13.5 CM.

Answer 1

Given :

I think Question is wrong . Instead Of B it should be G . Because it is said triangle EFG

Perimeter=13.5cm
F=60
°G=80°

To construct the required traingle

Steps of construction :
1. Draw PQ=13.5cm
2. draw PQS an angle 60°
3.With centre Q, draw an arc with any radius 
4. arc will intersect line PQ at T.
5.Now with same radius and centre as T draw another arc which intersect at U.
6. Join QU and extend it to S.
So that ∠PQS=60
7. Draw QPR an angle of 80 with the help of protractor.And take any radius and take centre as P draw an arc that intersect line PQ at X and line  PR at Y
8. With X and Y as centres . Now draw 2 arcs of convenient radius at W. Join PW and produce it. With T and U as centres we will draw 2 arcs of convenient at V.Join QV and produce it so that it intersect PW produced at E
9. Draw perpendicular bisector. LM
10. NO is perpendicular bisector of QE
11. Line LM intersect line PQ at G and line NO intersect PQ at F.
12 Now let us join EG and EF
The triangle EFG is only our required traingle.