Construct triangle LMN in which LM =6cm, MN =8cm and angle M =90 degree. Measure angle N. Also deaw a perpendicular bisector of MN
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construction
Step-by-step explanation:
- Draw a line segment MN = 8 cm
- at a point M , draw an angle of 90° with the help of compass or ruler
- taking M as a center , draw an arc of 6 cm which cuts PM at point L.
- join LN .
- The measure of the angle N must be less than 90°
steps to draw perpendicular bisector of MN
- Given a line segment MN
- open the compass more than half of the distance between M and N, and scribe arcs of the same radius centered at M and N.
- Call the two points where these two arcs meet C and D. Draw the line between C and D.
- CD is the perpendicular bisector of the line segment MN.
#Learn more:
Construct a right angled triangle lmn right angle at n and lm=mn=6.2cm
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