Question

construct triangle pqr in whichpq=5.8 qr+pr=8.4 cm and angle q=60°

Answer 1

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Answer 2

construct triangle pqr in whichpq=5.8 qr+pr=8.4 cm and angle q=60°

Steps of construction:

Step 1: Draw a line segment PQ=5.8cm

Step2: At point q construct an angle XQP=60⁰ using a compass.

Step3: From QX, Cut a line segment QS=8.4cm

Step4: Join PS

Step5 : Draw a perpendicular bisector of PS meeting SQ at R.

Step 6: Join PR

Step 7: Therefore, TRIANGLE ABC IS TZE REQUIRED TRIANGLE....

JUSTIFICATION....

'R' lies on the perpendicular bisector of PS

PR=RS

QS=8.4cm

QR+RS= 8.4cm

QR+PR=8.4cm [PR=PS]

3.4 CM+5CM=8.4 CM