Question

construct triangle pqr such that angle Q is equals to hundred degree QR is equal to 6.4 cm a angle R is equal to 50 degree and construct its circumcircle​

Answer 1

Answer:

First draw a base QR 6.4 cm

then draw two angles 100°at point Q and 50° at point R

and at which the rays intersect the point is P

this is your required triangle