Question

Construct triangle pqr such that pq=7.5cm, qr=6cm, angle q=55°

Answer 1

$\triangle pqr$ is the required triangle.

Step-by-step explanation:

Given,

Construct $\triangle pqr$ such that $pq=7.5\ cm,qr=6\cm, \angle q=55\ degree$

Following steps:

• Draw a line segments $pq=7.5\ cm$ using scale.
• At point $q$, draw an angle $55\ degree$ using protector like $\angle pqx=55\ degree$
• Take $q$ as a center and $6\ cm$ as radius draw an arc which cuts the line $qx$ at $r$
• Join $pr$

Now, $\triangle pqr$ is the required triangle.