Math, asked by shaikaman2286, 1 year ago

Construct Δ XYZ with XY = 4 cm, YZ = 6 cm and XZ = 3 cm.

Answers

Answered by nikitasingh79
25

FIGURE IS IN THE ATTACHMENT..

Given :

In Δ XYZ with XY = 4 cm, YZ = 6 cm and XZ = 3 cm.

Steps for construction :

1.Draw a line segment XY = 4 cm

2. From vertex X draw an arc of radius 3 cm the help of compass.

3.From vertex Y draw an arc of radius 6 cm the help of compass intersecting the previous arc.

4. The point of intersection is Z.

5. Join XZ & YZ

∆XYZ is a required triangle.

HOPE THIS ANSWER WILL HELP YOU...

Attachments:
Answered by gogiya167
9

Step for constriction of triangle.

1.Draw a line segment XZ = 3 cm

2. From vertex X draw an arc M of radius 4 cm the help of compass.

3.From vertex Z draw an arc N of radius 6 cm the help of compass.

4.Take intersection of the M and N arc.

4. The point of intersection is y.

5. Join XY & YZ

Hope it helps

Thanks


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