Construct Δ XYZ with XY = 4cm, YZ = 6cm and XZ = 3cm.
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For constructing Δ
1.Draw a line from X to Y ( XY = 4 cm. )using scale.
2.Now keep bow compass at X and extend it till 3 cm. and draw a arc M.
3.Similarly keep bow compass at Y and extend it till 6 cm. and draw a arc N such that its intersect with the M.
4.Give name point of intersection Z.
5.By joining point XZ and YZ we got ΔXYZ.
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It is given that ,
In ∆XYZ ,
XY = 4 cm , YZ = 6 cm , XZ = 3 cm
Draw a rough diagram as I shown above .
Construction steps :
1 ) Draw YZ = 6 cm line segment.
2 ) Take Y and Z as centers with 4 cm and
3 cm radius draw arcs which intersects
each other at X .
3 ) Join X to Y and Z .
We get required ∆XYZ .
I hope this helps you.
: )
In ∆XYZ ,
XY = 4 cm , YZ = 6 cm , XZ = 3 cm
Draw a rough diagram as I shown above .
Construction steps :
1 ) Draw YZ = 6 cm line segment.
2 ) Take Y and Z as centers with 4 cm and
3 cm radius draw arcs which intersects
each other at X .
3 ) Join X to Y and Z .
We get required ∆XYZ .
I hope this helps you.
: )
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