constuct a parallelogram ABCD where BC=10 cm CD=8cm and<BCD=45°
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first take BC 10 cm . then keep the protector on point C mark 45⁰ . then take 8 cm measure in parkar and make an acr by keeping the pointer on point C. you see that CD is formed then make AD similarly and then join AB . you will find your parallelogram
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