Contact force (F.) between two bodies is the resultant of force of friction and normal reaction.
Contact force for shown position is (g = 10 ms?)
(A) 40N
(B) √1616 N
(C)4N
(D) None of these
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c)is a answer 4n......please follow me
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mg= N+20√2sin 45
6×10 = N+20√2sin45
N= 60-20√2 1/√2
N = 40
static = UsN
0.2 × 40 = 8
kinetic=UkN
0.1 × 40 = 4
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