Math, asked by Anonymous, 1 year ago

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find two digit number whose HCF is 24 and LCM is 144

Answers

Answered by Anonymous
11
Hey!

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LCM×HCF= Product of two numbers

LCM= Product of number/HCF

Let two number be y,z

LCM=(y×z)/HCF

LCM=(y×z)/24

144=(y×z)/24

yz=144×24

yz=(2×2×2×2×3×3)×(2×2×2×3)

yz=(2^4×3²)×(2³×3¹)

yz=(2^4×3³)×(3²×3¹)

yz=2^7×3³

yz=3456

HCF=24

LCM=HCF

3456 and 24

yz=(24,144) (48,72) (72,48) (144×24)

So 2 digits are 48 and 72

LCM=144 and HCF=24

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Regards :)

Yash Raj ✌
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Anonymous: nice
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