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find two digit number whose HCF is 24 and LCM is 144
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Hey!
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
LCM×HCF= Product of two numbers
LCM= Product of number/HCF
Let two number be y,z
LCM=(y×z)/HCF
LCM=(y×z)/24
144=(y×z)/24
yz=144×24
yz=(2×2×2×2×3×3)×(2×2×2×3)
yz=(2^4×3²)×(2³×3¹)
yz=(2^4×3³)×(3²×3¹)
yz=2^7×3³
yz=3456
HCF=24
LCM=HCF
3456 and 24
yz=(24,144) (48,72) (72,48) (144×24)
So 2 digits are 48 and 72
LCM=144 and HCF=24
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
Regards :)
Yash Raj ✌
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
LCM×HCF= Product of two numbers
LCM= Product of number/HCF
Let two number be y,z
LCM=(y×z)/HCF
LCM=(y×z)/24
144=(y×z)/24
yz=144×24
yz=(2×2×2×2×3×3)×(2×2×2×3)
yz=(2^4×3²)×(2³×3¹)
yz=(2^4×3³)×(3²×3¹)
yz=2^7×3³
yz=3456
HCF=24
LCM=HCF
3456 and 24
yz=(24,144) (48,72) (72,48) (144×24)
So 2 digits are 48 and 72
LCM=144 and HCF=24
®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®
Regards :)
Yash Raj ✌
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Anonymous:
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