Question

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★ STANDARD QUESTION 46 ★

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Question is -

For what values of m does the equation x² - x + m = 0 posses no real roots ?


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Answer 1

The equation here is x^2-x+m=0
So a=1 b=-1 & c=m.
For an equation to have no real roots the discriminant should be lesser than zero.
So ,
Discriminant = b^2 - 4ac
b^2 -4ac < 0.
-1^2 - 4*1*m <0
1 - 4m < 0
m < 1/4
So all the values of less than 1/4 of m the equation will have no real or imaginary roots.

Answer 2

The eqn x^2-x+m=0. has no real roots when m>1/4
Refer to the attachment below for the solution.
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