Question

Contract a triangle LMN right angle m, given that LM =5cm MN=5cm.​

Answer 1

Here is your answer user.

Answer 2

Answer:

Here are steps of construction :

First of all draw a line segment MN = 3 cm

Using a compass draw an angle of 90° at M i.e. <NMQ =90°

(Using Pythagoras theorem we get LM = 4 cm )

Mark an arc on Ray MQ taking the radius of compass = 4 cm, name the point of intersection as L

Join L to N

∆LMN is the required triangle