If the slit width of YDSE are in the ratio 1/4 , then the ratio of maximum to minimum intensity on the screen is
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Answered by
64
Hola User_______________
Here is Your Answer..!!
_______________________
↪⭐Actually welcome to the concept of the WAVE OPTICS
↪Basically we know that ....
↪W1/W2 = I1 / I2 = A1^2 / A2^2
↪so applying this we get as
↪⭐The intensity of Imax to Imin will be obtained as
↪⭐Imax/ Imin = 9 / 1
________________________
⭐〽Hope it helps u...☺
Here is Your Answer..!!
_______________________
↪⭐Actually welcome to the concept of the WAVE OPTICS
↪Basically we know that ....
↪W1/W2 = I1 / I2 = A1^2 / A2^2
↪so applying this we get as
↪⭐The intensity of Imax to Imin will be obtained as
↪⭐Imax/ Imin = 9 / 1
________________________
⭐〽Hope it helps u...☺
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SupermanINFINITY:
hey , You are in Allen
Answered by
37
ASSALAMUALAIKUM,
SOLUTION:-
intensity is directly proportional to the width of the slit and also directly proportional to square of amplitude....
then,
W1/W2 = I1/I2 = A^/B^
A^/B^ = 1/4
A/B = 1/2
B = 2A
I max./ Imin.
= (A+B)^ / (A-B)^
=9/1
=9:1 watts
INSHAALLAH it will help you!
SOLUTION:-
intensity is directly proportional to the width of the slit and also directly proportional to square of amplitude....
then,
W1/W2 = I1/I2 = A^/B^
A^/B^ = 1/4
A/B = 1/2
B = 2A
I max./ Imin.
= (A+B)^ / (A-B)^
=9/1
=9:1 watts
INSHAALLAH it will help you!
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