if x=-2 and y =1 by using an identity find the value of the following (i)(4y^2-9x^3)(16y^4+36x^2y^2+81x^4
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Heya!!!!!
Answer Of Your Question☺️
(I)(4y^2-9x^3)
={4(1)^2-9(-2)^3}
=(4+72)
=76
(ii)(16y^4+36x^2y^2+81x^4)
=16(1)^4+36(-2×1)+81(-2^4)
=16-72-1296
=-1352
Hope My Answer Helped
Answer Of Your Question☺️
(I)(4y^2-9x^3)
={4(1)^2-9(-2)^3}
=(4+72)
=76
(ii)(16y^4+36x^2y^2+81x^4)
=16(1)^4+36(-2×1)+81(-2^4)
=16-72-1296
=-1352
Hope My Answer Helped
AnsumanA:
but the answer is -46592
the answer was given in back side of math book
ok but answer me quick
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