Question

convert 0.5 m Ca( oH)2 into normality​

Answer 1

Explanation:

ANSWER

Moloes of OH

−

=

6.023×10

23

9.033×10

22

=0.15

∴ Moles of Ca(OH)

2

=

2

1

×0.15=0.075

Molarity =

500

0.075

×1000=0.15

Molarity = molarity × [n-factor of Ca(OH)

2

]

=0.15×2=0.3=

10

3